If we are exceedingly generous and assume an underlying 90% rate of votes going to Biden in that precinct, the odds of a continuous string X long of votes coming up Biden is
0.9 ^ X
So for X = 23277 we have
0.9 ^ 23277 = 8.0 × 10^-1066
For reference, there are approximately 10^82 atoms in the observable universe.
I can run that one! It's easy math.
If we are exceedingly generous and assume an underlying 90% rate of votes going to Biden in that precinct, the odds of a continuous string X long of votes coming up Biden is
0.9 ^ X
So for X = 23277 we have
0.9 ^ 23277 = 8.0 × 10^-1066
For reference, there are approximately 10^82 atoms in the observable universe.
This is a great comment LOLz.
with each vote a 99% likelihood of being a Biden vote it would still be 2.5 x10^-102, or alternatively a 1 in 398 duotrigintillion (99 zeros) chance
Very nice. Another way to look at it is to roll a 10 sided die, and do it 23,277 times. If you roll a 10, you need to stop. See if you can do it.
I got 14. Skunked again!
The year of the Norman invasion of Britain? That's truly mind boggling.
This is where they are harvesting votes from, unprecedented turnout for a weak candidate with no enthusiasm like Biden, yeah right, it’s pure fraud
That's because they guzzle communist ccp money like the rest of corporate America.
Fox News was covering Luzerne county today and assuring that everything was good and def no voter fraud!