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Burt_Reynolds 2 points ago +2 / -0

it would be more helpful if you just posted the % or registered voters that voted each year. What you have above makes sense to almost no one.

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ogpalpin [S] 1 point ago +1 / -0

Calculated the mean and standard deviations using past year's data as I stated. The calculations mean that there is a 99.9999% chance that the voter turnout was 57.6635 ±12.809.