E.g. Say Trump gets 1000 votes, Biden gets 700 = 1700 Total Votes
Apply algorithm (1000 * 0.7 = 700 for Trump, 700 * 1.3 = 910 for Biden)
1000 - 700 = 300 erred ballots for Trump, 700 - 910 = -210 erred ballots for Biden
300 + ABS(210) = 510 total erred ballots w/ 90 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
510 / 1700 = .30 or 30%, if you take 1-.3 you get .7 but isn't that technically the total of un-erred votes?
Sorry to be pedantic because I think your point is still valid and it didn't occur to me until you pointed it out.
EDIT: I see if you take 510 / 1610 = .316 which 1-.316 = .68 or 68%
No, it won't because its a rate. Rate's don't change based on their underlying values. The assumption is the algorithm used a ranked choice vote which allotted Trump .7 to Biden's 1.3. Because those rates are fixed you can through any number of ballots at the equation and it will always yield 30%. That doesn't mean however Biden always wins. In the example you gave Trump would still win in a landslide. This is what Sidney Powell meant by "we broke the algorithm". Trump got so many votes that the ranked choice point system couldn't flip the outcome so they had to rush in ballots.
Re-do the math to show me my example vs yours. I get different rates so just want to see what I'm doing wrong.
Scenario 1:
Apply algorithm (1000 * 0.7 = 700 for Trump, 700 * 1.3 = 910 for Biden)
1000 - 700 = 300 erred ballots for Trump, 700 - 910 = -210 erred ballots for Biden
300 + ABS(210) = 510 total erred ballots w/ 90 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
I see if you take 510 / 1610 = .316 which 1-.316 = .68 or 68%
Scenario 2:
Apply algorithm (3000* 0.7 = 2100 for Trump, 500 * 1.3 = 650 for Biden)
3000 - 2100 = 900 erred ballots for Trump, 650 - 500 = 150 erred ballots for Biden
900 + 150 = 1050 total erred ballots w/ 750 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
I see if you take 1050 / 2750 = .338 which 1-.338= .381 or 61.8%
The ratio of the total votes changes because you're eliminating 30% of votes for trump and creating 30% for Biden (a smaller number). I could probably create a function showing their relationship but I'm pretty baked right now.
When you watch a video of election officials clearing out a room to "stop counting" but continuing to count unobserved, id weigh that its more likely the courts are corrupt than the evidence is wrong.
It's there; you just don't want to do your own research to find it. Plus affidavits, mathematical proof, mysterious dumps in the middle of the night. WAKE UP. YOU'RE the problem. Your willful ignorance and sticking your head in the sand to what's really going on.
Isn't it more like an error rate of 30%?
E.g. Say Trump gets 1000 votes, Biden gets 700 = 1700 Total Votes
Apply algorithm (1000 * 0.7 = 700 for Trump, 700 * 1.3 = 910 for Biden)
1000 - 700 = 300 erred ballots for Trump, 700 - 910 = -210 erred ballots for Biden
300 + ABS(210) = 510 total erred ballots w/ 90 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
510 / 1700 = .30 or 30%, if you take 1-.3 you get .7 but isn't that technically the total of un-erred votes?
Sorry to be pedantic because I think your point is still valid and it didn't occur to me until you pointed it out.
EDIT: I see if you take 510 / 1610 = .316 which 1-.316 = .68 or 68%
Error rate varies based on number of votes for each candidate. If you use 3000 for Trump and 500 for Biden it's much different.
No, it won't because its a rate. Rate's don't change based on their underlying values. The assumption is the algorithm used a ranked choice vote which allotted Trump .7 to Biden's 1.3. Because those rates are fixed you can through any number of ballots at the equation and it will always yield 30%. That doesn't mean however Biden always wins. In the example you gave Trump would still win in a landslide. This is what Sidney Powell meant by "we broke the algorithm". Trump got so many votes that the ranked choice point system couldn't flip the outcome so they had to rush in ballots.
Re-do the math to show me my example vs yours. I get different rates so just want to see what I'm doing wrong.
Scenario 1: Apply algorithm (1000 * 0.7 = 700 for Trump, 700 * 1.3 = 910 for Biden) 1000 - 700 = 300 erred ballots for Trump, 700 - 910 = -210 erred ballots for Biden
300 + ABS(210) = 510 total erred ballots w/ 90 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
I see if you take 510 / 1610 = .316 which 1-.316 = .68 or 68%
Scenario 2:
Apply algorithm (3000* 0.7 = 2100 for Trump, 500 * 1.3 = 650 for Biden) 3000 - 2100 = 900 erred ballots for Trump, 650 - 500 = 150 erred ballots for Biden
900 + 150 = 1050 total erred ballots w/ 750 leftover votes which you either dump into third party or distribute however you wish, doesn't affect the desired outcome.
I see if you take 1050 / 2750 = .338 which 1-.338= .381 or 61.8%
The ratio of the total votes changes because you're eliminating 30% of votes for trump and creating 30% for Biden (a smaller number). I could probably create a function showing their relationship but I'm pretty baked right now.
I was saying it was the same because I was using 1050 / 3500 (the original total number) which gives 0.300.
Your ratio is changing because if you use the new total (i.e. 2750) it doesn't include your tossed out 750.
Equation for error rate is:
1 - .3(T+B) / (.7T +1.3B)
Hehe
When you watch a video of election officials clearing out a room to "stop counting" but continuing to count unobserved, id weigh that its more likely the courts are corrupt than the evidence is wrong.
Its seems dishonest to day no evidence, while preventing anyone from investigating.
It's there; you just don't want to do your own research to find it. Plus affidavits, mathematical proof, mysterious dumps in the middle of the night. WAKE UP. YOU'RE the problem. Your willful ignorance and sticking your head in the sand to what's really going on.
Bye! Good luck in your own little hell hole!