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BigFreedomBoner 15 points ago +16 / -1

He claims that because we are not dealing with several orders of magnitudes, Benford's law does not apply.

I see the point. Most results are in the hundreds. A few in the 10 and a few in the thousands. That is the precincts were created to all be of similar size.

But what about the second numbers and following?

But Benfords law applies to the second numbers and following digits as well. He mentions that himself.

And then at 14:11 he totally torches himself. Trumps last two digits are in line with Benford's Laws (I like how he acts like this is evidence of Trump's fraud lol) where are Biden's are similar to the random generated Pi digit pairs.

BUT AGAIN. I REPEAT. HE IS ACCUSING TRUMP OF FRAUD!

So why does your claimed source accuse Trump of election fraud? Do you still stand by this turkey? Or is this just part of some disinformation campaign you are running? I'd really like some answers. Do you think Trump committed election fraud? If so, why not just come out and say it. If not, then why are you linking to such bullshit artists?

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bingobangobongo69 4 points ago +5 / -1

Benford's law is a statement about the first digit, not the last two digits. At that point he's talking about a different "law" that has an even distribution given certain conditions.

He doesn't actually say Trump committed fraud, it's an act to showcase that an "anomalous" result given a certain "law" is NOT proof of fraud once you actually take a closer look and figure out the "law" is not applicable. I guess you closed the video before he explained why Trump's result is actually completely expected and not proof of any anomaly... which he did like a minute later.

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BigFreedomBoner 3 points ago +3 / -0

I knew absolutely nothing of Benford's law before this post. I am just telling you he said subsequent digits followed the law as well. If he is wrong about that, then I retract my claim.

I clearly see the point that Benford's does not apply if you have all numbers only between 100-999. As it would make lotteries impossible. Or give premium to betting on numbers between 100-199.

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bingobangobongo69 4 points ago +5 / -1

Subsequent digits from the left may follow the law, but that doesn't mean it applies to the last two digits. I can see why you'd intuit that it should be applicable since if you keep going to through the subsequent digits, you eventually cover them all including the last two.

But the key insight you missed is that as the data crosses multiple orders of magnitude, the reading order (left to right) itself starts to matter. The second digit in 2319 is in the hundreds, while the second digit in 12319 is in the thousands. Meanwhile, if you were to look at the last digit instead, it doesn't change as you increase the orders of magnitude. It's always in the ones.

Indeed, the last digit is nine in both cases when looking at it from the right, but if you were to look at it from the left, it's the 4th digit in the first case and the 5th digit in the second case. That's why Benford's law would not be applicable to something that specifies "last digits" rather than "first digits".

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BigFreedomBoner 3 points ago +3 / -0

Thank you for the explanation.

Also realizing this is how "numbers rackets" worked. It was always the last digits of some publicly available data.. i.e, last three digits of the Dow Jones I think it one my dad help out on when he was a kid in the 50s. Before the states ran lotteries, number rackets were at every job site.